152=-16t^2+154t+110

Solution for 152=-16t^2+154t+110 equation:

152=-16t^2+154t+110

We move all terms to the left:

152-(-16t^2+154t+110)=0

We get rid of parentheses

16t^2-154t-110+152=0

We add all the numbers together, and all the variables

16t^2-154t+42=0

a = 16; b = -154; c = +42;
Δ = b2-4ac
Δ = -1542-4·16·42
Δ = 21028
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21028}=\sqrt{4*5257}=\sqrt{4}*\sqrt{5257}=2\sqrt{5257}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-154)-2\sqrt{5257}}{2*16}=\frac{154-2\sqrt{5257}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-154)+2\sqrt{5257}}{2*16}=\frac{154+2\sqrt{5257}}{32}
$